5x-1/6x-9-5x-10/8x^2-18=9x-4/8x-12

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Solution for 5x-1/6x-9-5x-10/8x^2-18=9x-4/8x-12 equation: 


x in (-oo:+oo)

5*x-((10/8)*x^2)-((1/6)*x)-(5*x)-18-9 = 9*x-((4/8)*x)-12 // - 9*x-((4/8)*x)-12

5*x-((10/8)*x^2)-((1/6)*x)-(5*x)-(9*x)+(4/8)*x-18-9+12 = 0

(-5/4)*x^2+5*x+(-1/6)*x-5*x-9*x+(4/8)*x-18-9+12 = 0

-5/4*x^2-26/3*x-15 = 0

DELTA = (-26/3)^2-(-15*(-5/4)*4)

DELTA = 1/9

DELTA > 0

x = ((1/9)^(1/2)+26/3)/(-5/4*2) or x = (26/3-(1/9)^(1/2))/(-5/4*2)

x = -18/5 or x = -10/3

x in { -18/5, -10/3 }

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